Correct option is 22nπ−π6,2nπ+7π6

Questions

Solve $\sin x > \frac{- 1}{2}$

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2nπ−π6,2nπ+π6

2nπ−π6,2nπ+7π6

2nπ−π4,2nπ+7π4

2nπ−π6,2nπ+5π6

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detailed solution

Correct option is B

We have sinx>−12⇒−π6

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Solve sinx>−12

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Solve $\sin x > \frac{- 1}{2}$