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Questions  

 Solve xy2e1x3dxx2ydy=0

a
3x2=2y2e1/x2+cx2
b
3y2=2x2e1/x3+cx2
c
y=2x2e1/x3+cx2
d
x2=2ye1/x2+cx2

detailed solution

Correct option is B

Differential Equation can be written as ydydx-y2x=−e1/x3x2 Put y2=t⇒ydydx=12dtdx I.F =e−2∫1/xdx=1x2t1x2=∫1x2⋅−2x2e1/x3dx=∫−2x4e1x3dxy2x2=23e1/x3+c⇒3y2=2x2e1x3+cx2

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