Solve xy2−e1x3dx−x2ydy=0
3x2=2y2e1/x2+cx2
3y2=2x2e1/x3+cx2
y=2x2e1/x3+cx2
x2=2ye1/x2+cx2
Differential Equation can be written as ydydx-y2x=−e1/x3x2 Put y2=t⇒ydydx=12dtdx I.F =e−2∫1/xdx=1x2t1x2=∫1x2⋅−2x2e1/x3dx=∫−2x4e1x3dxy2x2=23e1/x3+c⇒3y2=2x2e1x3+cx2