A square is inscribed in the circle x2+y2−2x+4y−93=0with its sides parallel to the coordinate axes. The coordinates of its vertices, are

Let x=a,x=b,y=c,y=d be the sides of the square. The length of each diagonal of the square is equal to the diameter of the circle ∴  Diagonal =21+4+93=142Let  I be the length of each side of the square. Then,  2I2=( Diagonal )2⇒2l2=(142)2⇒l=14 .Therefore, each side of the square is at a distance 7 from the centre  (1, - 2) of the given circle. This implies that  a=−6,b=8,c=−9,d=5Hence, the vertices of the square are (-6,-9), (-6,5), (8,-9), (8, 5).