Q.
Square of the length of the greatest common tangent to the circles given by x2+y2−4=0 and x2+y2−12x+27=0 is ____.
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answer is 35.
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Detailed Solution
For circle,k2+y2−4=0, centre is C1(0,0)and radius is r1=2.For circle, x2+y2−12x+27=0, centre is C2(6,0)and radius is r2=3.Length of greatest common tangent =C1C22−r1−r22=36−1=35
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