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A is square matrix satisfying the equation  A24A5I=O. Then  A1=

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a
A−4I
b
13A−4I
c
14A−4I
d
15A−4I

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detailed solution

Correct option is D

A2−4A−5I=O⇒AA−4I=5I⇒A−1=15A−4I


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