First slide

Introduction to statistics

Question

Standard deviations for first 10 natural numbers is

Easy

A

5.5
B

3.87
C

2.97
D

2.87

Solution

we know that, SD of first n natural numbers $= \sqrt{\frac{n^{2} - 1}{12}}$
$∴$ SD of first lo numbers $= \sqrt{\frac{10^{2} - 1}{12}}$
$= \sqrt{\frac{100 - 1}{12}} = \sqrt{\frac{99}{12}} = \sqrt{8.25} = 2.87$

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