First slide

Introduction to statistics

Question

Standard deviations for first 10 natural numbers is

Moderate

A

2.87
B

5.5
C

3.87
D

2.97

Solution

$\begin{array}{l} We know that, SD of first n natural numbers = \sqrt{\frac{n^{2} - 1}{12}} \\ \begin{aligned} ∴ SD of first 10 numbers = \sqrt{\frac{10^{2} - 1}{12}} \\ = \sqrt{\frac{100 - 1}{12}} = \sqrt{\frac{99}{12}} = \sqrt{8.25} = 2.87 \end{aligned} \end{array}$

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