Statement I : Every function must be either even or odd function Statement II : The function f(x)=log(x+x2+1) is an odd function Which of the following is true
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a
ony I
b
only II
c
both I and II
d
neither I nor II
answer is B.
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Detailed Solution
I : is not true Ex :f(x)=x2+x+1 then f(−x)=x2−x+1≠f(x) or ≠−f(x) II : f(−x)=log((x2+1−x)x2+x+xx2+1+x) =−log(x+x2+1)=−f(x) odd functiononly II is true