Statement 1: I =
∫f(x)g′(x)−f′(x)g(x)f(x)g(x){logg(x)−logf(x)}dx=12logg(x)f(x)2+C
Statement 2: ∫(ϕ(x))nϕ′(x)dx=(ϕ(x))n+1n+1+C
STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1
STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation forSTATEMENT-1
STATEMENT-1 is True, STATEMENT-2 is False
STATEMENT-1 is False, STATEMENT-2 is True
I=∫logg(x)f(x)ddxlogg(x)f(x)dx=12logg(x)f(x)2+C
Put ϕ(x)=t in integral of statement -2.