First slide
Hyperbola in conic sections
Question

Statement-1: The locus of the point of intersection of the tangents that are at right angles to the hyperbola x236-y216=1 is the circle x2+y2=52

Statement-2: Perpendicular tangents to the hyperbola x2a2-y2b2=1 interest on the director circle  x2+y2=a2-b2a2>b2 of the hyperbola.

Moderate
Solution

Equation of a tangent to the hyperbola is y = mx+a2m2-b2 and the equation of the tangent perpendicular to it is y=-1mx+a2m2-b2.

Eliminating m we get the required locus as (y-mx)2 +(x+my)2=a2m2-b2+a2-b2m2

x2+y2=a2-b2 and the statement-2 is true using which statement-1 is false.

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