The statement p→(q→p) is equivalent to

p→(q→p)≡∼p∨(q→p)≡(~p)∨(~q∨p)≡(~q)∨(p∨~p)≡(~q)∨T=T∴ p→(q→p) is  a tautology. Also  p→(p∨q)≡∼p∨(p∨q)≡(~p∨p)∨q≡T∨q=T∴ ρ→(p∨q) ) is also a tautologyThus, p→(q→p)  is equivalent to p→(p∨q)