The statement p→(q→p) is equivalent to
p→(p→q)
p→(p∨q)
p→(p∧q)
p→(p↔q)
p→(q→p)≡∼p∨(q→p)≡(~p)∨(~q∨p)≡(~q)∨(p∨~p)≡(~q)∨T=T
∴ p→(q→p) is a tautology.
Also
p→(p∨q)≡∼p∨(p∨q)≡(~p∨p)∨q≡T∨q=T
∴ ρ→(p∨q) ) is also a tautology
Thus, p→(q→p) is equivalent to p→(p∨q)