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Introduction to mathematical reasoning
Question
The statement
p
⇒
(
q
⇒
p
)
is equivalent to
Easy
A
p
⇒
(
p
⇒
q
)
B
p
⇒
(
p
∨
q
)
C
p
⇒
(
p
∧
q
)
D
p
⇒
(
p
⇔
q
)
Solution
Hence
p
⇒
(
q
⇒
q
)
≡
p
⇒
(
p
∨
q
)
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