First slide

Rate Measure

Question

A stone projects vertically upward with initial velocity $116 f t / \sec$ moves according to the law $S = 116 t - 16 t^{2}$ the acceleration at $t = 2$ seconds is

Moderate

A

$32 unit / \sec^{2}$
B

$32 unit / \sec$
C

$- 32 unit / \sec^{2}$
D

$- 32 unit / \sec$

Solution

$S = 116 t - 16 t^{2}$
$v = 116 - 32 t$

$a = - 32 {unit/sec}^{2}$

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