A straight line L through the point (3$$,−$$2) is inclined at an angle $$60$$∘ to the line $$3x+y=1$$ . If L also intersects the x $$-axis$$, then the equation of L is

Correct option is 2y−3x+2+33=0

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$A straight line L through the point (3, - 2) is inclined at an angle 60^{\circ} to the line \sqrt{3} x + y = 1 . If L also intersects$
$the x -axis, then the equation of L is$

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y+3x+2−33=0

y−3x+2+33=0

3y−x+3+23=0

3y+x−3+23=0

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detailed solution

Correct option is B

Let the slope of the required line be m. Thenm+31−3m=3 or m+3=±(3−3m) or 4m=0 or m=0 and 2m=23 or m=3Therefore the equation is y+2=3(x−3)(m≠0 as given that line cuts the x -axis) or 3x−y−(2+33)=0

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A straight line L through the point (3,−2) is inclined at an angle 60∘ to the line 3x+y=1 . If L also intersects the x -axis, then the equation of L is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

$A straight line L through the point (3, - 2) is inclined at an angle 60^{\circ} to the line \sqrt{3} x + y = 1 . If L also intersects$
$the x -axis, then the equation of L is$