Q.

A straight line l1 with equation x−2y+10=0 meets the circle with equation x2+y2=100 at B in the first quadrant. A line through B, perpendicular to l1 cuts y-axis at P (0, t). the value of ‘t’ is

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a

12

b

15

c

20

d

25

answer is C.

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Detailed Solution

Slope of l1=12Slope of l2=−2Equation of l2 , y=−2(x−10)⇒y+2x=20Hence, t=20
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A straight line l1 with equation x−2y+10=0 meets the circle with equation x2+y2=100 at B in the first quadrant. A line through B, perpendicular to l1 cuts y-axis at P (0, t). the value of ‘t’ is