A straight line through point A ( 3, 4) is such that its intercept between the axes is bisected at A. Its equation is

Let the equation of the line be xa+yb=1. lt cuts the coordinates axes at P(a,0) and Q(0,b). It is given that PQ is bisected at  A (3, 4).∴ a+02=3 and 0+b2=4⇒a=6,b=8.Hence, the equation of the line is x6+y8=1 or, 4x+3y=24.