Q.

A straight line through point A ( 3, 4) is such that its intercept between the axes is bisected at A. Its equation is

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a

x+y=7

b

3x-4y+7=0

c

4x+3y=24

d

3x+4y=25

answer is C.

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Detailed Solution

Let the equation of the line be xa+yb=1. lt cuts the coordinates axes at P(a,0) and Q(0,b). It is given that PQ is bisected at  A (3, 4).∴ a+02=3 and 0+b2=4⇒a=6,b=8.Hence, the equation of the line is x6+y8=1 or, 4x+3y=24.
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