A straight line through the point A(3, 4) is such that its intercept between the axes is bisected at A. Its equation is

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3x+4y=25

x+y=7

3x-4y+7=0

4x+3y=24

answer is D.

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Detailed Solution

Let the equation be xa+yb=1 where a2=3, b2=4⇒ a=6, b=8 and the required equation is 8x+6y=48 or 4x+3y=24

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