A straight line with slope 2 and y-intercept 5 touches the circle. x2+y2+16x+12y+c=0 at a point Q. then the co-ordinates of Q are
(−6,11)
(−9,−13)
(−10,−15)
(−6,−7)
Let Q=x1,y1. Then
we have y1=2x1+5 and y1+6x1+8×2=−1
⇒x1=−6 and y1=−7