Questions
The straight line intersects the
Circle in points P and Q. The coordinates of
the point of intersection of tangents drawn at P and Q to the circle are
detailed solution
Correct option is B
Let the required point be Rx1,y1 Then, PQis the chord of contact of tangents drawn from Rx1,y1 tox2+y2=25 So, the equation of PQ is xx1+yy1=25This equation and x−2y+1=0 represent the same line. ∴ x11=y1−2=−251⇒x1=−25 and y=50Hence, the required point is ( - 25, 50)Talk to our academic expert!
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