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Questions  

 The straight line y=m(x-a) meets the parabola y2=4ax in  two distinct points for =

a
all m∈R
b
all m∈[-1,1]
c
all m∈R-{0}
d
None of these

detailed solution

Correct option is C

substitute the expression for y  in the equation of the parabolamx−a2=4axm2x−a2=4axm2x2−4ax−2am2x+a2m2=0m2x2+x−4a−2am2+a2m2=0This is a quadratic equation, if it has two roots, its discriminant must be positive4a+2am22−4m2a2m2>02+m22−m4>0m4+4m2+4−m4>04m2+1>0For any non zero value of m this is possible

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