The straight lines 4x−3y−5=0,x−2y=0, 7x+y−40=0 and x+3y+10=0 form
a rectangle
a parallelogram
a cyclic quadrilateral
none of these
tanA=12+71−72=−3
tanC=43+131−43×13=3
⇒tan(A+C)=0⇒A+C=180∘
⇒ABCD is a cyclic quadrilateral.