The straight lines x + y = 0,3x + y = 0, and x + 3y - 4 = 0 form a triangle which is
isosceles
equilateral
right-angled
None of these
Solving the given equations of lines pairwise, we get the vertices of triangle as A(1,2), B(2, -2), C(1,1). Then,
AB=16+16=42BC=1+9=10CA=9+1=10
Hence, the triangle is isosceles.