A stralght line passing through P(3,1)meets the coordinate axes at A and B. It is given that the distance of this straight line from the origin O is maximum. The area of triangle OAB is equal to
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a
503 sq.units
b
253 sq.units
c
203 sq.units
d
1003 sq.units
answer is A.
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Detailed Solution
Line AB will be the farthest from the origin if OP is right angled to the line drawn. OP=10Also, tanθ=13OA=OPsecθ=10×103=103OB=OP cosecθ=10×101=10∴Area of ΔOAB=12(103)(10)=503