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Questions  

 The sum of all integral value(s) of ' r ' for which the circles 

x2+y210x+16y+89r2=0 and x2+y2+6x14y+42=0 intersect in two real distinct points is

a
219
b
119
c
191
d
120

detailed solution

Correct option is B

We have (x−5)2+(y+8)2=25+64+r2−89 And (x+3)2+(y−7)2=49+9−42=16⇒(x−5)2+(y+8)2=r2 and (x+3)2+(y−7)2=(4)2⇒(5,−8) (−3,7)⇒65+225=289=17= distance between their centres  Now, |r−4|<1717⇒r>13 And −17

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How many common tangents can be drawn to the following circles x2+y2=6x and x2+y2+6x+2y+1=0?


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