The sum of all the real roots of the equation|x−2|2+|x−2|−2=0  is

Putting y = |x – 2|, we can rewrite (1) as                           y2+y−2=0 or y2+2y−y−2=0⇒                      y(y+2)−(y+2)=0⇒(y−1)(y+2)=0As                    y=|x−2|≥0,y+2≥2∴                      y−1=0⇒y=1⇒                     |x−2|=1⇒x−2=±1⇒                     x=2±1⇒x=3 or 1∴                      Sum of the roots = 4