Questions
The sum of all two digit numbers which when divided by 4, yield unity as remainder, is
detailed solution
Correct option is C
The first two digit number which when divided by 4 leaves remainder 1 is 4 .3 + 1 = 13 and last is 4 . 24 + 1 = 97.Thus, we have to find the sum13+17+21+…+97which is an A.P.∴ 97=13+(n−1)⋅4⇒n=22 and Sn=n2[a+l]=11×[13+97]=11×110=1210.Similar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
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