The sum of the coefficient of all odd degree terms in the expansion of x+x3−15+x−x3−15,x>1
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a
0
b
1
c
2
d
-1
answer is C.
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Detailed Solution
We know that (x+a)5+(x-a)5=2C0 5x5+C2 5x3a2+C4 5xa4∴x+x3-15+x-x3-15=2C0 5x5+C2 5x3x3-1+C4 5xx3-12=2C0 5x5+C2 5x6-x3+C4 5xx6-2x3+1Thus, the sum of coefficient of all odd degree terms =2C0 5-C2 5+C4 5+C4 5=2[1-10+5+5]=2