The sum of the coefficients of even power of x in the expansion of 1+x+x2+x35 is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
256
b
128
c
512
d
64
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
1+x+x2+x35=a0+a1x+a2x2+a3x3+⋯+a15x15Putting x = 1 and x = -1 alternatively, we havea0+a1+a2+a3+⋯+a15=45 (1)a0−a1+a2−a3+⋯−a15=0 (2)Adding (1) and (2), we have2a0+a2+a4+⋯+a14=45or a0+a2+a4+⋯+a14=29=512