First slide

Binomial theorem for positive integral Index

Question

Sum of the coefficients of ${(1 + 2 x + 3 x^{2})}^{5} =$

Easy

A

$6^{5}$
B

$7^{6}$
C

$5^{6}$
D

$3^{2}$

Solution

Given expansion ${(1 + 2 x + 3 x^{2})}^{5}$ is then

Sum of the coefficients of ${(1 + 2 x + 3 x^{2})}^{5}$ is in place of $x$ by 1

$f (x) = {(1 + 2 x + 3 x^{2})}^{5}$ substitute $x = 1$

$f (1) = {(1 + 2 + 3)}^{5}$

$= 6^{5}$

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