First slide
Trigonometric equations
Question

The sum of distinct solutions of the equation 4tanx+tan2x+1=22sinx+π41+tan2x in the interval  0,π  is:

Difficult
Solution

                          4tanx+sec2x=22sinx+π4sec2x4sinxcosx+1=2sinx+cosx

                             2sinx2cosx-1-2cosx-1=0

                              sinx=12,cosx=12x=π6,5π6,π3

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