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Questions  

The sum of distinct solutions of the equation 4tanx+tan2x+1=22sinx+π41+tan2x in the interval  0,π  is:

a
π2
b
4π3
c
d
7π6

detailed solution

Correct option is B

4tanx+sec2x=22sinx+π4sec2x⇒4sinxcosx+1=2sinx+cosx                           ⇒  2sinx2cosx-1-2cosx-1=0                              sinx=12,cosx =12⇒x=π6,5π6,π3

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