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The sum of first n terms of the series 11!+22!+33!+44!+ is 

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a
(n+1)!−1
b
n!−1
c
(n−1)!−1
d
None of these

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detailed solution

Correct option is A

Let Sn=1⋅1!+2⋅2!+3⋅3!+4⋅4!  +…+n×n!⇒ Sn=(2−1)1!+(3−1)2!+(4−1)3!  +(5−1)4!+…+[(n+1)−1]n! =(2⋅1!−1!)+(3⋅2!−2!)+(4⋅3!−3!)  +(5⋅4!−4!)+…+[(n+1)n!−n!] =(2!−1!)+(3!−2!)+(4!−3!)+(5!−4!)+…+[(n+1)!−n!] =(n+1)!−1!=(n+1)!−1


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