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Q.

The sum of the first n terms of the series 12+2.22+32+2.42+52+. Is n(n+1)22, when n is even, when 'n' is odd sum is

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a

n(n+1)22

b

n2(n+1)2

c

n(n+1)24

d

3n(n+1)2

answer is B.

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Detailed Solution

If n is odd, the required sum is 12+2.22+32+2⋅42+52+..+2(n−1)2+n2=(n−1)n22+n2=n2(n+1)2

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