Q.

The sum of the first n-terms of the series 3+75+243+507+… is 4353 then n is

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a

18

b

15

c

13

d

29

answer is B.

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Detailed Solution

given that 31+5+9+13+…+Tn=4353⇒n2[2+4(n−1)]=435⇒2n2−n−435=0       n=15
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