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The sum of the first ten terms of the series
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a
100
b
99
c
102
d
101
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Correct option is D
852+1252+1652+..+4452_ since 10'th term of the A.P=8+9·45=162522+32+..+112=162511(11+1)(22+1)6−1 since sum of the squares of first n natural numbers=nn+12n+16=1625×505=165×101=165m⇒m=101Similar Questions
The sum of terms of an is The number of term which equals 159, is
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