The sum of the first ten terms of the series 1352+2252+3152+42+4452+.. is 165m then m is
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a
100
b
99
c
102
d
101
answer is D.
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Detailed Solution
852+1252+1652+..+4452_ since 10'th term of the A.P=8+9·45=162522+32+..+112=162511(11+1)(22+1)6−1 since sum of the squares of first n natural numbers=nn+12n+16=1625×505=165×101=165m⇒m=101