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The  sum of first 24 terms of the A.P, a1,a2,a3,.... if it is known that  a1+a5+a10+a15+a20+a24=225

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a
700
b
800
c
900
d
600

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detailed solution

Correct option is C

We known that in an A.P the sum of the termsequidistant  from the beginning and end is always same and is equal tothe sum of first and last term, ie. a1+an=a2+an−1=a3+an−2=.....So if an A.P. consists  of 24 terms, then a1+a24=a3+a20=a10+a15a1+a5+a10+a15+a20+a24=225⇒a1+a24=2253=75∴S24=242a1+a24usin⁡gSn=n2a1+an=12(75)=900( using (i))


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