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a
38+1220
b
39+1219
c
39+1220
d
38+1219
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Correct option is D
General term of the given series 2.2r−12r,r≥0 Required sum =1+∑i=119 2.2r−12r Now ∑r=119 2.2r−12r=∑s=119 2−12r=2×19−121−12191−1/2=38+1219−1 since sum of n terms in G.P=a1-rn1-r=37+1219 Required sum=1+37+1219=38+1219Similar Questions
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