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Q.

The sum ∑i=0m(10 i) ( 20m−i) is maximum when m is

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a

5

b

10

c

15

d

20

answer is C.

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Detailed Solution

∑i=0m(10 i) ( 20m−i) =10c0.20cm+10c1.20cm−1+−−−+10cm.20c0 = 30cm which is maximum , when m=15 ( C(n,r) maximum value is C( n,n2) , if n is even )

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