First slide
Combinations
Question

The sum i=0m(10  i) (   20mi) is maximum when m is

Easy
Solution

i=0m(10  i) (   20mi) =10c0.20cm+10c1.20cm1++10cm.20c0 

                               =    30cm  which is maximum , when m=15    

                                           ( C(n,r) maximum value is C( n,n2)  , if n is even  )

 

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