The sum ∑i=0m(10 i) ( 20m−i) is maximum when m is
5
10
15
20
∑i=0m(10 i) ( 20m−i) =10c0.20cm+10c1.20cm−1+−−−+10cm.20c0
= 30cm which is maximum , when m=15
( C(n,r) maximum value is C( n,n2) , if n is even )