The sum ∑i=0m(10i)(20m−i) , (where(pq)=0 if p<q) is maximum when m is
5
15
10
20
∑i=0m(10i)(20m−i)=∑i=0m10Ci20Cm−i
= 30Cm
Which is maximum when m=n2 =15
(∵ nCr is maximum for r=n2 when n is odd)