Sum of an infinite G.P. is 2 and sum of their cubes is 24, then 5th term of the G.P. is

a1−r=2,a31−r3=24∴8(1−r)31−r3=24⇒1−2r+r21+r+r2=3⇒2r2+5r+2=0⇒r=−2,−1/2As |r|<1,r=−1/2,a=3Now, t5=ar4=3/16