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The sum of the infinite series 1+43+932+1633+ is

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a
4/2
b
9/2
c
4/9
d
1

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detailed solution

Correct option is B

This is clearly not an arithmetico-geometric series,since 1, 4, 9, '16, ... are not in AP. However, their successive differences (4 - 1), (9 - 4), (16 - 9) ,... are in AP.LetS∞=1+43+932+1633+…∞13S∞=13+432+933+…∞On subtraction, we get23S∞=1+33+532+733+…∞⇒13⋅23S∞=13+332+533+…∞ multiplying both sides by 13On subtracting the two series, we get49⋅S∞=1+23+232+233+…∞=1+231+13+132+…∞=1+23×11−13=2∴ S∞=2×94=92


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The sum of the first n  terms of the series

12+2.22+32+2.42+52+2.62+..........  is n(n+1)22,  when n  is even. When n  is odd the sum is


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