The sum of intercepts on the axes of coordinates by any tangent to the curve x+y=2 is
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a
2
b
4
c
8
d
22
answer is B.
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Detailed Solution
For the curve x+y=2 , the parametric coordinates are given by x=2cos2θ and y=2sin2θ i.e., x=4cos4θ And x=4sin4θ dydx=4×4sin3θ.cosθ4×4cos3θ(−sinθ)=−tan2θ ⇒Eq. of tangenty−4sin4θ=−tan2θ(x−4cos4θ) ∴ x−intercept=|4cos4θ+4sin4θtan2θ|=4cos2θ and ∴ y−intercept=|4sin4θ+4sin4θtan2θ|=4sin2θ Hence, the sum of intercept made on the axes of coordinates is 4cos2θ+4sin2θ=4