The sum of the intercepts of the plane which bisects the line segment joining (0,1,2) and (2,3,0) perpendicularly is

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answer is 2.

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Detailed Solution

The plane equation is 2x(x2−x1)+2y(y2−y1)+2z(z2−z1)+x12+y12+z12−x22−y22−z22=0where (x1,y1,z1)=(0,1,2) and (x2,y2,z2)=(2,3,0)

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