Q.

The sum of last two digits of the number 7101 is

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answer is 7.

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Detailed Solution

7101=7(49)50=7(1−50)50=7 50C0−50C150+50C2502−…=7[1+100λ] where λ∈N=7+700λ Therefore, last two digits of number 7101 are 07 .
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