First slide

Binomial theorem for positive integral Index

Question

$The sum of the middle term s in the expansion of (\sqrt{3} + \sqrt{2})^{9}$

Very Easy

A

5
B

6
C

11
D

1

Solution

n = 9 (even)
$\begin{array}{l} Middle terms = \frac{n + 1}{2}, \frac{n + 3}{2} \\ = \frac{9 + 1}{2}, \frac{9 + 3}{2} \\ = 5, 6 \\ Sum = 5 + 6 = 11 \end{array}$

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