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The sum to n terms of the sequence is
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a
n2loga2rn−1
b
nloga2rn−1
c
3n2loga2rn−1
d
None of these
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Correct option is A
The given sequence can be expressed asloga,(loga+logr),(loga+2logr)…which is clearly an A.P. whose first term is log a and common difference is log r.The nth term =loga+(n−1)logrSince sum to n terms s=n2a1+an∴ Sn=n2[loga+loga+(n−1)logr]=n2[2loga+(n−1)logr]=n2loga2rn−1Similar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
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