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Sum to n terms of the series 1+(1+2)+(1+2+ 3) +is 

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a
12n(n+1)(n+2)
b
13n(n+1)(n+2)
c
14n(n+1)(2n+1)
d
16n(n+1)(n+2)

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detailed solution

Correct option is D

tr=1+2+…+r=12r(r+1)=12r2+r∑r=1n tr=1216n(n+1)(2n+1)+12n(n+1)=16n(n+1)(n+2)


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Let m be a positive integer, then S=k=1mk1k+1k+1+1k+2++1m is equal to :


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