The sum to n terms of the series
113+1+213+23+1+2+313+23+33+…is
nn+1
n2(n+1)
2nn+1
nn(n+1)
If tn denotes the nth term of the series, then
tn=1+2+3+⋯+n13+23+33+⋯+n3=12n(n+1)14n2(n+1)2=2n(n+1)=21n−1n+1
⇒ ∑k=1n tk=2112+1213+⋯+ 1n−1n+1 =21−1n+1=2nn+1