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The sum to n terms of the series 17+10+110+13+113+16+is

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a
13(7+3n−7)
b
4+3n−23
c
13(10+3n−10)
d
none of these

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detailed solution

Correct option is A

We have           tr=14+3r+7+3r=7+3r−4+3r3Thus, sum to n terms is equal to13[(10−7)+(13−10)+⋯+(7+3n−4+3n)]=13(7+3n−7)


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