The sum to n terms of the series 17+10+110+13+113+16+⋯is
13(7+3n−7)
4+3n−23
13(10+3n−10)
none of these
We have tr=14+3r+7+3r=7+3r−4+3r3Thus, sum to n terms is equal to13[(10−7)+(13−10)+⋯+(7+3n−4+3n)]=13(7+3n−7)