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Q.

The sum of 1+n1−1x+n(n+1)2!1−1x2+⋯∞ will be

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a

xn

b

x-n

c

1−1xn

d

1-1x-n

answer is A.

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Detailed Solution

1+n1−1x+n(n+1)2!1−1x2+⋯∞              =1−n−1−1x+−n(−n−1)2!−1−1x2+⋯∞=1−1−1x−n=xn
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The sum of 1+n1−1x+n(n+1)2!1−1x2+⋯∞ will be