The sum of the non-real roots of x2+x−2x2+x−3=12 is

Put x2+x=y,so that Eq. ( 1) becomes(y−2)(y−3)=12or y2−5y−6=0or (y−6)(y+1)=0 or y=6,−1When y = 6, we getx2+x−6=0⇒ (x+3)(x−2)=0 or x=−3,2When y = 1, we getx2+x+1=0which has nonreal roots and sum of roots is -1.